calculate the percentage composition of phosphorus in zinc phosphate
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Explanation:Ca3( PO4)2
atomic mass of calcium ( Ca) = 40 g/mol
atomic mass of phosphorus ( P) = 31 g/mol
atomic mass of Oxygen ( O) = 16 g/mol
molecular mass of C3(PO4)2 = 3 × 40 + 2× (31+ 64) = 120 + 2 × 95 = 120 + 190
= 310 g/mol
now,
% of Ca in Ca3(PO4)2 = 3×40/310 × 100
= 1200/31 % = 38.7 %
% of P in Ca3(PO4)2 = 2×31/310 × 100
= 20 %
% of O in Ca3(PO4)2 = 8 × 16/310 × 100
= 1280/31 = 41.3 %
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