Question

Calculate the percentage efficiency of a motor that does of 60J of work from 240J of electrical energy.



answer pls

Answer 1

Answer:

Given :-

• A motor that does of 60J of work from 240J of electrical energy.

To Find :-

• What is the percentage efficiency of a motor.

Formula Used :-

$\clubsuit$ Percentage Efficiency Formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Efficiency =\: \dfrac{Useful\: Energy\: Output}{Total\: Energy\: Input} \times 100}}}\: \: \: \bigstar$

Solution :-

Given :

• Useful Energy Output = 60 J
• Total Energy Input = 240 J

According to the question by using the formula we get,

$\footnotesize \implies \bf Efficiency =\: \dfrac{Useful\: Energy\: Output}{Total\: Energy\: Input} \times 100$

$\implies \sf Efficiency =\: \dfrac{60}{240} \times 100$

$\implies \sf Efficiency =\: \dfrac{60 \times 100}{240}$

$\implies \sf Efficiency =\: \dfrac{600\cancel{0}}{24\cancel{0}}$

$\implies \sf Efficiency =\: \dfrac{\cancel{600}}{\cancel{24}}$

$\implies \sf Efficiency =\: \dfrac{25}{1}$

$\implies \sf\bold{\red{Efficiency =\: 25\%}}$

$\therefore$ The percentage efficiency of a motor is 25% .

Answer 2

Answer:

25%

Explanation:

Input energy= 240 J

Output energy= 60J

Efficiency= {input energy×100}\output energy

Efficiency= 60×100/240

Efficiency=25%