Chemistry, asked by Bushrasajid, 1 month ago

Calculate the percentage in Na2Co3 (Na=23,O=16,C=12)

Answers

Answered by firdous41

Answer:

Percentage of Sodium [Na] in Sodium Carbonate [Na2CO3] = 46/106 x 100 = 43.40%. Percentage of Carbon [C] in Sodium Carbonate [Na2CO3] = 12/106 x 100 = 11.32%. Percentage of Oxygen [O] in Sodium Carbonate [Na2CO3] = 48/106 x 100 = 45.28%

Answered by mavimahlu43

Answer:

2316.12%

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Calculate the percentage in Na2Co3 (Na=23,O=16,C=12)​

Answers

Calculate the percentage in Na2Co3 (Na=23,O=16,C=12)