Calculate the percentage ionization of 0.01 m acetic acid in 0.1 m hcl ka of acetic acid is 1.8 10-5
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Hlw mate
Alpha = 1.8 × 10 ^ -5 / 0.1
= 1.8 ×10 ^ -4
Percentage = 1.8 × 10 ^ -4 × 100
= 0.018%
Hope it helpful
Alpha = 1.8 × 10 ^ -5 / 0.1
= 1.8 ×10 ^ -4
Percentage = 1.8 × 10 ^ -4 × 100
= 0.018%
Hope it helpful
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