Question

Calculate the percentage loss of mass of hydrated copper [II] Sulphate when it is completely dehydrated.

Atomic wts are Cu = 64, S = 32, O =16 and H = 1

Answer 1

HOLA friend!!
Rajdeep here....

What is the formula of Hydrated Copper sulphate?
It is CuSO₄.5H₂O

Now, molecular mass of 1 crystal of copper sulphate is:
64 + 32 + (4x16) + 5(2x1 + 16)
= 96 + 64 + 5x18
= 160 + 90
= 250.

Now, Find out the mass of copper sulphate when 5 molecules of water of crystallization is removed:
It is CuSO₄ 
= 64 + 32 + (4x16)
= 96 + 64
= 160.

What is the loss in mass?
It is (250 - 160) = 90g

Now, what is the percentage loss in mass?
Original mass was 250g. So, we will take it in our calculation.

Percentage loss = 
[tex] \frac{90}{250} \times 100 \\= 0.36 \times 100 \\= 36[/tex]%

Hence, percentage loss in mass is 36%

Thanks!!

Answer 2

Answer:

What is the formula of Hydrated Copper sulphate?

It is CuSO₄.5H₂O

Now, molecular mass of 1 crystal of copper sulphate is:

64 + 32 + (4x16) + 5(2x1 + 16)

= 96 + 64 + 5x18

= 160 + 90

= 250.

Now, Find out the mass of copper sulphate when 5 molecules of water of crystallization is removed:

It is CuSO₄

= 64 + 32 + (4x16)

= 96 + 64

= 160.

What is the loss in mass?

It is (250 - 160) = 90g

Now, what is the percentage loss in mass?

Original mass was 250g. So, we will take it in our calculation.

Percentage loss =

\begin{lgathered}\frac{90}{250} \times 100 \\= 0.36 \times 100 \\= 36\end{lgathered}

250

90

×100

=0.36×100

=36

%

Hence, percentage loss in mass is 36%

Thanks!!

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