calculate the percentage loss of mass when sodium carbone crystals are heated strongly
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alculate the percentage composition of each of the elements present in pure calcium carbonate (Ca = 40, C = 12, O = 16).
Solution:
Mass of one mole of pure calcium carbonate (CaCO3)
= Mass of calcium + Mass of carbon + Mass of oxygen
= (40 x 1) + (12 x 1) + (16 x 3)
= 40 + 12 + 48
= 100 g
Solution:
Mass of one mole of pure calcium carbonate (CaCO3)
= Mass of calcium + Mass of carbon + Mass of oxygen
= (40 x 1) + (12 x 1) + (16 x 3)
= 40 + 12 + 48
= 100 g
jagroopjoshi:
Plz tell the percentage of carbon plz
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