Question

Calculate the percentage of carbon in 55% of pure sample of CaCO3

Answer 1

u should know such a easy answer dude

Answer 2

Answer : The percentage of carbon in 55% of pure sample of $CaCO_3$ is, 6.6%

Solution : Given,

Molar mass of $CaCO_3$ = 40 + 12 +3(16) = 100 g/mole

As, percentage of carbon in 100% pure $CaCO_3$ = $\frac{12}{100}\times 100=12\%$

So, percentage of carbon in 55% pure $CaCO_3$ = $\frac{55}{100}\times 12\%=6.6\%$

Therefore, the percentage of carbon in 55% of pure sample of $CaCO_3$ is, 6.6%