Question

calculate the percentage of carbon in a 55% pure sample of carbon carbonate [Ca= 40,C =12,O=16] answer is 6.6 percent

Answer 1

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Answer 2

:Answer : The percentage of carbon in 55% of pure sample of is, 6.6%

Solution : Given,

Molar mass of = 40 + 12 +3(16) = 100 g/mole

As, percentage of carbon in 100% pure = CaCO3 is 12%

So, percentage of carbon in 55% pure = 55/100×12%=6.6%

Therefore, the percentage of carbon in 55% of pure sample of is, 6.6%