Calculate the percentage of SO4 and H2O in pure crystals of Mohr's salt
Answers
Answered by
14
Answer:
Explanation:
Chemical formula of Mohr's salt = (NH₄)₂Fe(SO₄)₂·6 H2O
Molar mass of Mohr's salt = 14 x 2 + 4 x 1 x 2 + 56 + 32 x 2 + 16 x 4 x 2 + 6 x 18
= 392 g/mole
From the chemical formula, we can see that there are 2 moles of SO₄ and 6 moles of water in Mohr's salt
Mass of SO4 in Mohr's salt = (32 + 4 x 16) x 2 = 196
Mass of water in Mohr's salt = 6 x 18 = 128 g
Percentage of SO₄ = (Mass of SO₄/Mass of Mohr's salt) x 100
= (196/392) x 100
= 50%
Percentage of H₂O = (Mass of H₂O/Mass of Mohr's salt) x 100
= (128/392) x 100
= 32.65 %
Answered by
0
Answer:
Explanation:
Utcugs
Similar questions