Question

calculate the pH and pOH of 0.5m solution of HCL​

Answer 1

Answer:

pH = log 1/ [H+]

HCl is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)

pH = log 1/5 x 10^-1 which equals=0.30

Answer 2

pH = log 1/ [H+]

pH = log 1/ [H+]HCI is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)

pH = log 1/ [H+]HCI is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)pH = log 1/5 x 10^-1 which equals=0.30

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