calculate the pH and pOH of 0.5m solution of HCL
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pH = log 1/ [H+]
HCl is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)
pH = log 1/5 x 10^-1 which equals=0.30
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pH = log 1/ [H+]
pH = log 1/ [H+]HCI is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)
pH = log 1/ [H+]HCI is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)pH = log 1/5 x 10^-1 which equals=0.30
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