Question

Calculate the pH at equivalence point when a solution of 0.1M acetic acid is titrated with a solution of 0.1M sodium hydroxide. Ka for acetic acid =1.9*10^-5

Answer 1

Answer:

ph=8.86

Explanation:

x²/0.1-x=Kw/Ka⇒x=7.26*10^-6= [OH⁻]

ph=log Kw/[OH⁻]=8.86