Calculate the pH at equivalence point when a solution of 0.1M acetic acid is titrated with a solution of 0.1M sodium hydroxide. Ka for acetic acid =1.9*10^-5
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Answer:
ph=8.86
Explanation:
x²/0.1-x=Kw/Ka⇒x=7.26*10^-6= [OH⁻]
ph=log Kw/[OH⁻]=8.86
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