Chemistry, asked by Hemanth1030, 1 year ago

calculate the pH at which an acid indicator with K is equal to 1 into 10 ^ - 5 changes colour when indicator is 1 into 10 to the power minus 3 moles

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Answered by dhakatanishqddun
3
hey...

An acid indicator has a Ka=3×10^-5. The acid form of the indicator is red and the basic form is blue. By how much must the pH change in order to change the indicator from 75% red to 75% blue? Ans is ∆pH= 0.954
An acid indicator has a Ka=3×10^-5.
The acid form of the indicator is red and the basic form is blue. By how much must the pH change in order to change the indicator from 75% red to 75% blue?
Ans is ∆pH= 0.954

Hemanth1030: Thanks
Hemanth1030: But the answer is wrong
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