if p=(2-a),prove that a³+6ap+p³-8=0
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Answered by
4
2-a=0
a=0-2
a=-2
,,,,,,,,,,,,,,,,,,,
p(x)=-2
p(-2)=(-2)^3+6(-2)p+p^3-8=0
=-8+12p+p^3-8
=-3p^3 is your answee....
,,,,,,,,,,.............,,,,,,,,,,,,,,,,:)
a=0-2
a=-2
,,,,,,,,,,,,,,,,,,,
p(x)=-2
p(-2)=(-2)^3+6(-2)p+p^3-8=0
=-8+12p+p^3-8
=-3p^3 is your answee....
,,,,,,,,,,.............,,,,,,,,,,,,,,,,:)
Laxmikum:
bro
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i know i have got already this types of que in h.w
ok
bye
and i appreciate your try
good luck
^ ^
Answered by
3
Answer:
2-a=0
a=0-2
a=-2
p(x)=-2
p(-2)=(-2)^3+6(-2)p+p^3-8=0
=-8+12p+p^3-8
=-3p^3
Step-by-step explanation:
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