Chemistry, asked by 10crasika, 6 months ago

calculate the Ph of 0.001M HNO3

2.If the Ph of a solution is 4.5 what is its pOH?

3.Calculate the Ph of an aqeous solution of sulfuric acid is 5 x 10-5 mol/lit

4.Calculate the PH of 1 x 10-4 molar solution of sodium hydroxide.

5.Lemon juice has a Ph 2, What is the concentration of H+ ions.

6.An organic compound A is widely used as a preservative and has the molecular formula C2H4O2. This compound reacts with ethanol to form a sweet smelling compound B.

i). Identify the compound A

ii).Write the chemical equation for its reaction with ethanol to form cpd B iii). Name the process.

7. WRITE IUPAC NAME FOR THE FOLLOWING COMPOUNDS:



1.CH3-CH2-CH2-COOH

2.CH3-CO-CH2-CH2-CH3

3.CH3-CH2-CH2-CH(CH3)-CH2-OH

4.CH3-CH2-CH2-CH2-CH2-CHO

5.CH3-CH(OH)-CH2-CH3

6.CH3-CH=CH-CH2-CH3



WRITE MOLECULAR FORMULA FOR THE FOLLOWING:



1.3-METHY HEXANE

2.PROPANOIC ACID

3. 3-PENTANONE

4. 2-PENTENE

5. 2-METHYL BUTAN-1-OL



Answers

Answered by sangeethailaiyaraja1
1

Answer:

1.0.001 M HNO3 = pH 2.0.

2.You are given that the pH = 4.5. Find the hydroxide ion concentration of a solution with a pOH of 5.90. To solve this, use a scientific calculator and enter 5.90 and use the +/- button to make it negative and then press the 10x key. On some calculators, you can simply take the inverse log of -5.90.

3. In aqueous solution fully dissociates to H+ and A−. pH of ... Example: Calculate the pH of 0.06 mol/L HCl. ... 03.10. 2018. 5. Calculating the pH of strong acid solutions.

4.

p

H

=

10

Explanation:

In water the following equilibrium operates:

2

H

2

O

(

l

)

H

3

O

+

+

H

O

As for any equilibrium, we can write the equilibrium expression:

[

H

3

O

+

]

[

H

O

]

[

H

2

O

]

=

K

'

w

Since

[

H

2

O

]

is huge, we can simplify this expression:

[

H

3

O

+

]

[

H

O

]

=

K

w

At

298

K

,

[

H

3

O

+

]

[

H

O

]

=

K

w

=

10

14

Taking

log

10

of both sides:

log

10

[

H

3

O

+

]

+

log

10

[

H

O

]

=

log

10

(

10

14

)

=

14

Now we can define

p

H

=

log

10

[

H

3

O

+

]

, and

p

O

H

=

log

10

[

H

O

]

.

And thus

p

O

H

+

p

H

=

14

(finally!)

Thus

p

O

H

of

1

×

10

4

m

o

l

L

1

NaOH

=

log

10

(

1

×

10

4

)

=

4

Since

p

O

H

+

p

H

=

14

,

p

H

=

10

5.pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9, base

6.Answer. (a) Compound A with molecular formula C2H4O2 is ethanoic acid, also called acetic acid. Its structural formula is CH3COOH. A dilute solution of acetic acid called vinegar is used as a preservative of pickles

,

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