Question

calculate the pH of 0.02 m H2SO4​

Answer 1

Answer:

Solving for pH

pH=−log[H+]

pH=−log0.04

pH=1.4

Therefore the pH is 1.4

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Answer 2

The pH of 0.02 M $H_2SO_4$ is 1.4

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

According to stoichiometry,

1 mole of $H_2SO_4$ gives 2 mole of $H^+$

Thus 0.02  moles of $H_2SO_4$ gives =$\frac{2}{1}\times 0.02=0.04$ moles of $H^+$

Putting in the values:

$pH=-\log[0.04]$

$pH=1.4$

Thus pH is 1.4

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