Question

calculate the ph of 0.056 M NH4OH(Kb=1.8×10⁵ M at 25°C​

Answer 1

Answer

OH

−

]=

K

b

×C

=

1×10

−5

×10

−1

=

10

−6

=10

−3

K

w

=[H

+

][OH

−

]

10

−14

=[H

+

][10

−3

]

[H

+

]=10

−11

Hence, pH=−logH

+

−log(1×10

−11

)=11

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