Question

calculate the ph of 1.00×10^-4 molar solution of HNO3​

Answer 1

Answer:

$\displaystyle \sf \longrightarrow 5$

Explanation:

Given :

$\displaystyle \sf Concentration [ \ H^+ \ ] = 1.00\times10^{-4} \ M$

We are asked to find pH :

We know :

$\displaystyle \sf pH=-\log [ \ H^+ \ ]$

Putting values here we get :

$\displaystyle \sf pH=-\log [ \ 1.00\times10^{-4} \ ]$

$\displaystyle \sf pH=-\log [ \ 10.0\times10^{-5} \ ]$

Using log rule :

$\displaystyle \sf \longrightarrow \log a^x=x. \log a$

$\displaystyle \sf \longrightarrow \log 10=1$

$\displaystyle \sf \longrightarrow pH=-(-5).\log [ \ 10.0 \ ]$

$\displaystyle \sf \longrightarrow pH=5.\log [ \ 10.0 \ ]$

$\displaystyle \sf \longrightarrow pH=5\times1$

$\displaystyle \sf \longrightarrow pH=5$

Hence we get required answer!