Calculate the pH of a 0.85 M solution of the weak base, aniline, C6H5NH2. The Kb of aniline is 3.8 x 10-10.
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Explanation:
Since pyridine is a weak base.
C
2
H
5
N+H
2
O⟶C
2
H
5
N
+
H+OH
−
t=0 0.2 0 0
c −x +x +x
at eqlb 0.2−x x x
k
b
=
[C
2
H
5
N
..
]
[C
5
H
5
N
+
H][OH
−
]
1.5×10
−9
=
0.2−x
x
2
x
2
=3×10
−10
x=1.73×10
−5
⇒[OH
−
]=1.73×10
−5
M
pOH=4.76
⇒pH=14−4.76=9.24
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