calculate the PH of a sample of soft drink whose H3O+ ion concentration in 3.8 x 10 -3M (log 3.8 = 0.589)
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H3O+] = 3.8 x 10-3
pH = – log [H3O+] = – log (3.8 x 10-3)
= – (log 3.8 – 3 log 10)
= – log 3.8 + 3.0 = – 0.589 + 3 = 2.42
The pH of a sample of soft drink whose hydronium ion concentration is 3.8 x 10-3 M is equal to 2.42
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