calculate the pH of a solution consist of 100 ml semi molar HNO3 and 10 ml of .01 M HCl solution
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Answered by
1
Answer:
Explanation:
apply formula m1v1+m2v2/v1+v2
and applying these we get
.45
which is concentration of h plus
ph=-log h plus
ph=-log .45
ph=log 100/45
ph=2-log45
ph=2-1.65
ph=.35
Answered by
0
Answer:
ormula m1v1+m2v2/v1+v2
and applying these we get
.45
which is concentration of h plus
ph=-log h plus
ph=-log .45
ph=log 100/45
ph=2-log45
ph=2-1.65
ph=.35
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