Question

Calculate the ph of a solution obtained by mixing equal volumes of the solution with ph=3 ph =5

Answer 1

I am just guessing.

If two solutions of equal volume are mixed but one has pH=3 and the other have pH=5, then pH could be 2 or -1 maybe because both are acidic and the product will also have an acidic nature. And will be a very strong acid.

Answer 2

Answer:

Explanation:

ph of solution 1= 3

h plus = 10^-3

ph of solution 2=5

h plus = 10^-5

total h plus=

10^-3+10^-5 /2

10-5(1+10^2)/2

10^-5(101)/2

ph=-log hplus

= -log 10^-5(101) /2

=-{-5+log 101 } - log 2

= -{-5+log 1.01*10^2 } -log 2

-{-5+2+log 1.01 }- log 2

-{-3+0.003 } -log 2

-{-2.997} - log 2

2.997 -0.3

2.697