Calculate the ph of a solution obtained by mixing equal volumes
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pH can be converted to concentration using formula,
concentration= -antilog(pH)
thus concentration of pH 3=10^(-3) & concentration of pH 5= 10^(-5)
now assuming 1 litre of solution of both,
M1V1+M2V2=M3V3
[10^(-3)*1]+[10^(-5)*1]=2*M3 (as V1+V2=V3)
0.00101/2=M3
thus the concentration obtained would be= 0.000505 M
pH=-log(concentration)= 3.29
hope this helps!
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