Question

Calculate the pH of the given solution: 0.3 g of NaOH dissolved in water to give 200 mL of solution.

Answer 1

For 0.3 g of NaOH dissolved in water to give 200 mL of solution is given below

NaOH →  Na +(aq)  + OH-(aq)

[NaOH] = 0.3 x 1000/200 = 1.5M

[OH-(aq)] = 1.5M

Then [H+]  =  10-14 / 1.5

= 6.66 x 10-13

pH  =  -log ( 6.66 x 10-13)

= 12.18hence the solution is solved respectively