Question

Calculate the poh of 0.005M H2SO4 . (poh =11.699)

Answer 1

H2SO4 is a strong diprotic acid. The equation for ionization is H2SO4 -->2H+SO2/4 --Each molecule of acid gives 2 molecules of H+. The concentration of H+ ion is 2 x 0.005 = 0.010M

pH = −log[H+ ]=−log[0.01]=2.

pH = 2

Answer 2

Answer:

CaCalculate the poh of 0.005M H2SO4 . (poh =11.699)

Explanation:

CaCalculate the poh of 0.005M H2SO4 . (poh =11.699)