calculate the pOH of 0.007M aqueous solution of NaOH
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pOH = - log [OH-]
pOH = 1.14
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The pOH of 0.007M aqueous solution of NaOH can be simply found by using the equation, pOH = - log [OH-].
In the question, the OH has been mentioned and hence the pOH can be determined to be as 1.14. pOH can be defined as a measure of hydroxide ion (OH-) concentration in a solution.
It is a very important parameter for many purposes.
The pOH can be used to derive the alkalinity of a solution.
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