Question

calculate the point on the curvature y=logx when slope is 1

Answer 1

Please see the attachment

Answer 2

Heya!!!

Let the points be x1 and y1

Slope of y is given by its derivative

I,e

y1 = log ( x1 )



dy / dx = 1 / x1

dy / dx = 1 given slope = 1


1 / x1 = 1

x1 = 1

Now put value of x1 in above equation

y1 = Log ( 1 )


y1 = 0


So, the points are. ( 1 , 0 )

Remember ( 1 , 0 ) is tangent point.