Question

calculate the potential at a point due to a charge of 4×10-9c located 9×10-2m away from it​

Answer 1

Answer:   400 V

Explanation:

The electric potential at a distance r from charge q is given as,

$V = \frac{1}{4\pi \epsilon_0} \times \frac{q}{r}\\\\= 9 \times 10^{9} \times \frac{4 \times 10^{-9} }{9 \times 10^{-2} }\\\\=400 V$[ we have used the value of $\frac{1}{4\pi \epsilon_0} = 9 \times 10^{9} N m^2/ C^2$ ]