Question

calculate the potential at a point p due to a charge of 4✖10-7 located 9 CM away

Answer 1

q=4×10^-7
r=9cm=9×10^-2m
v=1/4π€ q/r
v=9×10^9×4×10^-7/3×10^-2
v=36×7×10²×10^-2/3
v=12×7=84 volt

hope it's helps

Answer 2

Answer:

Potential, V = 40000 Volts

Explanation:

It is given that,

Magnitude of electric charge, $q=4\times 10^{-7}\ C$

Distance at which the electric potential is to find, d = 9 cm = 0.09 m

Electric potential is given by :

$V=\dfrac{kq}{r}$

$V=\dfrac{9\times 10^9\times 4\times 10^{-7}}{(0.09)}$

V = 40000 Volts

So, the potential at point P is 40000 V.