calculate the potential at point p due to a charge of 4×10^-7 C located 9 CM away.(ii) hence obtain the work done in bringing a charge of 2×10^-9 from infinity to P does the answer depend on the path along which the charge is there brought.
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since,V=kq/r
V=9×10^9×4×10^-7/9×10^-2=4×10^4V
ii) Vp- Vinfinity=w/q
since Vinfinity=0
Vp×q=w
w=8×10^-5J
no it don't depend upon the path follow because electrostatic force is a conservative force
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