Question

Calculate the potential difference across the 4 ohm resistor in the given electrical circuit using kirchhoff law hy is It genet ally to obtain near the tnid poin•t of l" idge w it v. Calculate the potential difTet•enu• across the Sl resisi•yc given elect'ical circuit. using Kirchhoff's rules.

Answer 1

Explanation:

Given Calculate the potential difference across the 4 ohm resistor in the given electrical circuit using kirchhoff  law

• Now loop is ADCBA
• So we have – 2I1 + 8 – 6 + I2 = 0
• Or I2 – 2I1 = - 2
• I2 – 2I1 + 2 =  
• Now for loop DEFCD
• So we have - 4(I1 + I2) – I2 + 6 = 0
•     = - 4I1 - 4I2 – I2 + 6 = 0
•  =   - 4I1 – 5I2 + 6 = 0
• =   4I1 +  5I2 – 6 = 0
• So equations are  
• I2 – 2I1 + 2 = 0-----------------1
• 5I2 + 4I1 – 6 = 0-----------------2
• Multiply equation 1 by 5 we get
• 5I2 – 10 I1 + 2 = 0
• 5I2 + 4I1 – 6 = 0
• So – 14 I1 + 16 = 0
• Or I1 = 8/7
• I2 – 2(8/7) + 2 = 0
• Or I2 = 2/7
• Current across 4 ohm resistor will be
• I1 + I2
• = 2/7 + 8/7
• = 10/7
• Now v = IR
•           = 10/7 x 4
• Or v = 40/7 V

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Answer 2

Explanation:

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