Question

Consider a rectangular tank is 6m long,4m wide,2m high is flooting in mercury.the center of gravity of the rectangular tank is 1m above the bottom of the tank and depth of immersion of the rectangular tank is 1.6m.the metacentric hight

Answer 1

Answer:

please mark me as brainlist and thank you

Step-by-step explanation:

188

Answer 2

Metacentric height = 0.7375 m.

Given :

A rectangular tank is 6m long,4m wide,2m high is flooting in mercury.

Center of gravity of the rectangular tank is 1m above the bottom of the tank and depth of immersion of the rectangular tank is 1.6m.

To find :

Metacentric height.

Concept used :

Center of buoyancy = The centroid of the immersed part of floating body.

BM = $\frac{I}{V}$

GM = BM - BG

GM = Metacentric height.

Where     BM = Height of Center of buoyancy and meta center.

                I = Area moment of inertia.

               V = Volume submerged.

Explanation :

See below attached image.

V = Volume submerged  = 1.6 × 4 ×6

                                          = 38.4 m³ 

I =  Area moment of inertia.

 = $\frac{6^3\times2}{12}$

  = 36

BM = $\frac{I}{V}$  = $\frac{36}{38.4}$ = 0.9375 m

BG = 0.2 m From image attached below.              

So    GM = BM - BG

             = 0.9375 - 0.2

             = 0.7375 m.

Therefore, the metacentric height = 0.7375 m.

To learn more....

1)A rectangular floating body 20 m long is 5m wide The water line is 1.5 m above the bottom, if the centre of gravity is 1.8 m from the bottom then the metacentric height will be approximately​.

brainly.in/question/8154691