Physics, asked by jeremiahopeyemisyl, 5 months ago

calculate the potential energy of a stone of mass 0.5g thrown vertically upward with a velocity of 10m/s

Answers

Answered by Anonymous
0

Answer:

25

Explanation:

mgh=1/2mv^2

0.5*10*h=1/2*0.5*100

5h=25

h=5

PE=mgh

=0.5*10*5

=25

Answered by TheEmeraldBoyy
5

Gɪᴠᴇɴ :

\begin{gathered}\longmapsto\:\bf{Mass\:(m)\:=\:100\:g\:=\:0.1\:kg} \\ \end{gathered}

\begin{gathered}\longmapsto\:\bf{Velocity\:(v)\:=\:30\:m/s} \\ \end{gathered}

Tᴏ Fɪɴᴅ

The maximum potential energy gained by the stone.

Cᴀʟᴄᴜʟᴀᴛɪᴏɴ :

We know that,

✯ When body reaches the highest point, it's entire kinetic energy gets converted into potential energy, which is maximum.

Thus,

↝ Kinetic energy of a body is,

\begin{gathered}\red\bigstar\:\:{\underline{\orange{\boxed{\bf{\green{Kinetic\:energy\:=\:\dfrac{1}{2}\:{m}\:{v^2}\:}}}}}} \\ \end{gathered} ★

➛ \begin{gathered}\bf{Kinetic\:energy\:=\:\dfrac{1}{2}\times{0.1}\times{(30)^2}\:} \\ \end{gathered}

➛ \begin{gathered}\bf{Kinetic\:energy\:=\:\dfrac{1}{2}\times{0.1}\times{900}\:} \\ \end{gathered}

➛ \begin{gathered}\bf{Kinetic\:energy\:=\:\dfrac{1}{2}\times{90}\:} \\ \end{gathered}

➛ \begin{gathered}\bf\blue{Kinetic\:energy\:=\:45\:Joules} \\ \end{gathered}

Hence,

★ Here the maximum kinetic energy, i.e. 45 J is converted into potential energy (maximum).

➙ \begin{gathered}\bf\pink{P.E_{(max^m)}\:=\:45\:Joules} \\ \end{gathered}

[NOTE : Potential energy is maximum at highest point.]

\Large\tt{Therefore,}

The maximum potential energy gain by the stone is 45 J.

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