calculate the potential of zinc electrode in which the zinc Ion activity is 0.001 M
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According to Nernst equationEZn = E0Zn/Zn2+ − 0.0591n log 1oxidised speciesHere the cell is with only oxidised species Zn →→ Zn2+ + 2 e−EZn = −0.76 − 0.05912 log 10.001 = −0.8487 V
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