Question

Calculate the potential of zinc -zinc ion electrode in which the zinc ion activity is 0.001M? (E0 Zn/Zn+2 = -0.76V, R=8.314Jmol-1K -1 , F=96,500Cmol-1

Answer 1

Answer:

Here Zn is in the anode and Cu is in the cathode Ecell =Ecathode‑Eanode therefore ;Ecell=0.34‑(‑0.76) =1.10 V

Explanation:

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