calculate the power of am engine required to lift 105 kg of coal /hour from a mile 36 m deep.take g=10m/s^2.
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Power = potential energy / time
= mgh / time
= 105kg * 10*36m / 3600 sec
= 37800J / 3600 sec
= 10.5 W.
= mgh / time
= 105kg * 10*36m / 3600 sec
= 37800J / 3600 sec
= 10.5 W.
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