Question

Calculate the power of an engine required to lift 10s kg of coal per hour from a mine 360 m deep,

Answer 1

         Power = Work done / time

                 P   = mgh/t = 10 kg x 9.8 ms^-2 x 360 m / 3600 sec

                P    = 9.8 Watt

      please clarify what is this s with 10 kg u have written