Calculate the power of an engine which can lift 300 kg of water through vertical height 15m in 15 sec. Show the steps please. It's urgent.
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Answered by
8
Power = Work / time
work = force x displacement
force = mass x acceleration
mass = 300 kg
g = acceleration = 9.8 m/s^2
power = force x displacement / time
power = mass x acceleration x displacement / time
= 300 x 9.8 x 15 / 15
= 300 x 9.8 = 2940 watts = 2.94 KW
work = force x displacement
force = mass x acceleration
mass = 300 kg
g = acceleration = 9.8 m/s^2
power = force x displacement / time
power = mass x acceleration x displacement / time
= 300 x 9.8 x 15 / 15
= 300 x 9.8 = 2940 watts = 2.94 KW
Answered by
1
Given,
mass of water (m) =300kg
verticalheight(h)=15m,. time=15 sec
here ,
force = weight=m*g
Work done W=m*g*h
so,. power. =W/time
=(300×10*15)/15
=3000W
so, power of the engine=3000Watt=3KW
mass of water (m) =300kg
verticalheight(h)=15m,. time=15 sec
here ,
force = weight=m*g
Work done W=m*g*h
so,. power. =W/time
=(300×10*15)/15
=3000W
so, power of the engine=3000Watt=3KW
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