Calculate the power of the engine required to lift 90 metric tonnes of coal per hour from a coal mine of depth 200m.Given 1 metric tonne = 1000 kg
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The work done would be
mgh
90000*10*200 = 18*10^7
Power = work done /time
= 18*10^7 / 3600
= 0.005*10^7 units
mgh
90000*10*200 = 18*10^7
Power = work done /time
= 18*10^7 / 3600
= 0.005*10^7 units
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