Question

define
$v { }^{2} = u { }^{2 } + 2as$
by calculus method ​

Answer 1

Answer:

a=dv/dta =dv/dx * dx/dt (using chain rule)since dx/dt=va= v dv/dxa dx=v dva[dx]os =[v dv]uvas=[v 1+1/2]uvas=[v2/2]uvas=v2-u2/2therefore, 2as= v2-u2 .