Question

calculate the power of the engine required to lift and power 5 kg to cal per hour from the mine 360 m Deep(take g =10ms-2​

Answer 1

Answer:

m=10

5

kg,g=10ms

−2

,h=360m,t=1h=3600s

The work needed in lifting a mass m to a height h against the force due to gravity is W=mg×h

And, power, P=

t

W

=

t

mgh

∴P=

3600

10

5

×10×360

W=10

5

W=100kW

Answer 2

Explanation:

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