calculate the pressure exerted by 10*23 gas molecules each of mass 10*-22 gram in a container of volume 1 litre the root mean square speed is 10*5 5 centimetre per second inverse..
plz reply fast..?????
Answers
Answered by
11
Answer:
According to the question, the pressure exerted by 1023
gas molecules each of mass 10−22
g in a container of volume one litre. The rms speed is 105cmsec−1
It is given that, n = 1023
M = 10-22 gram.
V= 1 litre = 103 cm3
Urms=105 cmsec−1
PV = 1/3mnu2rms
P×10 3=1/3×10-22 ×1023× (105)2
P=3.3× 107 dynecm-2
Hence the answer is 3.3× 107 dynecm-2.
Answered by
3
see the above attachment
Attachments:
Similar questions