Question

calculate the pressure exerted by a person weighing 600 north. when she is

1= standing on her feet with the area of contact between each foot and floor bing 0.0015msquare
2= sitting on a chair with a total area of contact on the chair being0.101msquare

Answer 1

Answer:

Pressure = \dfrac{force}{area}

area

force

here Force = 600 N and Area =0.0015 m^{2}m

2

Pressure = \dfrac{600 N}{0.0015 m^{2}}

0.0015m

2

600N

= 4,00,000

Answer 2

Answer:

The pressure on standing on her feet is 400 kilo Pascals and the pressure on sitting on chair is approximately 6 kilo Pascals.

Explanation:

$F=600N$

$A₁=0.0015m²$

$A₂=0.101m²$

Pressure on standing on her feet:

$Pressure=\frac{F}{A1}$

$Pressure=\frac{600}{0.0015}$

$Pressure=400000Pa$

$Pressure=400kPa$

Pressure on sitting on chair:

$Pressure=\frac{F}{A2}$

$Pressure=\frac{600}{0.101}$

$Pressure=5940.59Pa$

$Pressure=5941Pa(approx.)$

$Pressure=5.941kPa(approx.)$

$Pressure=6kPa(approx.)$

Hope it helps.