Question

Calculate the pressure exerted by a square block of mass 5kg and side 2m.

Answer 1

Hello,

We already know that:
$pressure = \frac{thrust}{area}$
First work is to find thrust and area.
Now,
Thrust is the perpendicular force acting on the surface. Also, the thrust is equal to the weight of the object.
Now,
Mass = 5 kg
g = 9.8 m/sec²
So,
Weight = mg = 5 *9.8 = 49 N

Now,
Area of the surface in contact = side²
So,
Area =2² = 4m²

Now,
Pressure = thrust/area = 49/4 = 12.25 Pascal.


So, the pressure exerted is equal to 12.25 Pascal ( When g =9.8 m/sec²)

Hope this will be helping you