calculate the pressure exerted by submarine which applies a force of 2300 newton the dimensions of the submarine are 30 metre x 10 metre x 8 metre.
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Answer: Here, h=2000m,
ρ=10
3
kgm
−3
,
g=10ms
−2
The pressure outside the submarine is
P=P
a
+ρgh
where P
a
is the atmospheric pressure. Pressure inside the submarine is P
a
.
Hence, net pressure acting on the window is gauge pressure. Gauge pressure,
P
g
=P−P
a
=ρgh
=10
3
kgm
−3
×10ms
−2
×2000m
=2×10
7
Pa
Area of a window is A=50cm×50cm
=2500×10
−4
m
2
Force acting on the window is
F=P
g
A
=2×10
7
Pa×2500×10
−4
m
2
=5×10
6
N
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