Physics, asked by dknzpro01, 10 months ago

Calculate the pressure exerted , if the density of mercury is 13600kgm³ and the density of water is 1000kgm³. water=2 metres and mercury= 3 metres.

Answers

Answered by dipamcool2016
0

Answer:

Pressure on:

1. Water: 1.2*10⁵ Pa;

2. Mercury: 5*10⁵ Pa.

Explanation:

Given,

Density (p) of water = 1000 kg/m³

p of mercury = 13600 kg/m³

Height (h) of water = 2 m

h of mercury = 3 m

Atmospheric Pressure = 1.013*10⁵ Pa

Gravitational Force (g) = 9.8 m/s²

Pressure exerted on water = Atm. Pressure + hpg

= 101300+(2*1000*9.8) Pa

= 101300+19600 Pa

= 120900 Pa

Or,

= 1.2*10⁵ Pa

Pressure exerted on mercury = Atm. Pressure + hpg

= 101300+(3*13600*9.8) Pa

= 101300+399840 Pa

= 501140 Pa

Or,

= 5*10⁵ Pa

Hope this helps.

Answered by prajnishkumar96
0

Answer:

5*10(5)

Explanation:

I think ur answer is 5*10(5)

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