calculate the pressure exerted the floor by standing on both feet if the weight of a boy is 60 kg assume that the area of contact of each shoe is 6 cm by 25 cm
1 kg wt=10n
Answers
Answer:
HEY MATE
Pressure, P = 26666.7 Pa
Explanation:
Mass of the boy, m = 40 kg
Its weight is, W = F= m g = 40 × 10 = 400 N
Area of contact of each shoes, A = 6 cm × 25 cm = 150 cm² = 0.015 m²
Pressure exerted on the floor by the boy is defined as the force acting per unit area.
P=\dfrac{F}{A}P=AF
P=\dfrac{400}{0.015}P=0.015400
P = 26666.7 Pa
Hence, this is the required solution.
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Answer:
Hello mate, first we need the two quantities force and are but we don't have them so we can initially write the quantities through which we can derive the two quantities:
Mass(m) = 60 kg
Breadth(b)=6cm=0.06m
Length(l)=25cm=0.25m
Acceleration due to gravity(g)=10m/s^2(Mostly people take it as negative but in this case we have taken it positive just for convenience)
Force=ma
Force=(60*10)N
Area=l*b
Area=(0.25*0.06)m^2
Pressure=Force/Area
Pressure=(60*10)N/(0.25*0.06)m^2
Pressure=40000Pa
Ans. The pressure is 40,000 Pascals