Question

Calculate the quantity of heat required to convert 1.5kg of ice at 0 degree celsius to water at 15 degree celsius .

Answer 1

$\boxed{\bold \green{Answer}}$

Q = 11.25 Kcal

$\boxed{\bold \green{Explanation}}$

Given:

• m = 1.5kg = 1500 gm
• $T_1 = 0 \degree C$
• $T_</strong><strong>2</strong><strong> = </strong><strong>50 </strong><strong>\degree C$
• $s_{ice} = 0.5 \: \dfrac{Cal}{gm \degree C}$

To Find:

Heat required to convert the ice into water

Solution:

w.k.t,

$\boxed{dQ = msdT}$

$\mathsf{dQ = (1500gm)(0.5 \:\dfrac{Cal}{gm \degree C})(15-0) \degree C}$

$\mathsf{dQ = (150\: \cancel{ 0gm})(\dfrac{5}{\cancel{10}} \:\dfrac{Cal}{\cancel{gm \degree C}})(15 \cancel{\degree C}) }$

$\mathsf{dQ = (150)(5)(15)cal }$

$\mathsf{dQ = 11250cal}$

$\mathsf{dQ = 11.25 Kcal}$

Answer 2

Answer:

11250 cal

Explanation:

Given:

m = 1500 gm

$ΔT= 50 \degree K$

$s = \dfrac{1}{2} \dfrac{Cal}{gm \degree K}$

To Find:

Heat required to convert the ice into water

Solution:

$\boxed{\pink{Q = msΔT}}$

$\bold{Q = 1500 \times \dfrac{ 1}{2}\times 12}$

$\bold{Q = 150 \times 15 \times 15 }$

$\bold{Q = 11250cal}$