calculate the quantity of heat required to raise the temperature of 5 kg iron from 303 K to 343 K (specific heat capacity of iron is 460 J/kg K).
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Q = mS∆T
= 5 kg × 460 J/(kg K) × (343 K - 303 K)
= 92000 J
= 92 kJ
Quantity of heat required is 92 kJ
= 5 kg × 460 J/(kg K) × (343 K - 303 K)
= 92000 J
= 92 kJ
Quantity of heat required is 92 kJ
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