Question

calculate the r.m.s velocity of argon ( atomic mass =40) at N.T.P​

Answer 1

Answer:

V=12.237ms-1

Explanation:

V rms = $\sqrt{3RT/M}$

V = $\sqrt{3*6.63*10^{-34} } *300/40$

V = 12.237ms-1

T=300K

M=40kgmol-1

R=6.63*$10^{-34}$J

Answer 2

Answer:

V=12.237ms-1

Explanation:

V rms = \sqrt{3RT/M}

3RT/M

V = \sqrt{3*6.63*10^{-34} } *300/40

3∗6.63∗10

−34

∗300/40

V = 12.237ms-1

T=300K

M=40kgmol-1

R=6.6310^{-34}10

−3 J