Question

calculate the r net in the above resistor
​

Answer 1

Answer:

56

Explanation:

add 20+10+20+6 we will get answer

Answer 2

Answer:

Explanation:

Given :

• R1 = 20 Ω , R2 = 10 Ω , R3 = 20 Ω , R4 = 6 Ω are connected in series combination.

To Find :

• Net resistance, Rs.

Formula to be used :

If the resistance’s are linked in series, the series resistance is articulated as :-

• Rs = R1 + R2 + R3 + R4,.......Rn

Solution :

★Net resistance,

Rs = R1 + R2 + R3 + R4

⇒ Rs = 20 + 10 + 20 + 6

⇒ Rs = 30 + 26

⇒ Rs = 56 Ω

Hence, Net resistance is 56 Ω.

★More formulae,

If resistance is connected in parallel, the parallel resistance is given by :-

• 1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4,.......1/Rn

Ohm's law formula,

• V = IR